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 Posted: Thu 8:13, 21 Apr 2011 Post subject: Travel Faster and Stay Younger |
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v class="googleright">The prominent "twin ambiguity" of relativity was born in 1911, later Paul Langevin restated Einstein's time dilation of traveling clocks. It can be paraphrased as follows: "Pam, Jim's dual sister, undertakes a long, quite rapid space journey and aboard her return to Earth, finds her twin brother very a morsel older than herself".
Why is it a paradox? Skeptics of relativity dispute that after Pam has approached her cruising speed, she could think herself as at repose and that it's Jim that is rushing away from her at magnificent speed. In such a case, Pam must be aging faster than Jim. This is not the case whatever,Changing the Way People Interact,[link widoczny dla zalogowanych], as has been verified experimentally in particle accelerators many times.
The solution to the paradox lurks in the truth that Pam has been hastened fjust aboutme parts of the trip, meantime Jim has not. However, experiments have also shown that haste does not directly affect agreeable atomic (or biological) clocks. It is only the time that Pam spends traveling at the high speed relative to Jim that determines how many younger than Jim she will eventually be.
Einstein's relativity theory demands that space and time should be considered attach as an entity shrieked space-time. When Pam and Jim are attach and stationary on Earth, they both acquire the space-time movement of their situation on Earth. Since they do not move relative to that position, their space-time movements are the same as their time movements (the rate at which they grow older).
This earned rate of space-time movement remains constant for both twins. As soon as Pam moves away from Jim, the change in the rate of her space movement (SM) is "deducted" from the rate of her time movement (TM) in mandate to keep her gained rate of space-time movement (STM) constant. Actually, it is the squares of the rates that are added/subtracted, which can be stated like this:
STM squared = SM squared + TM squared = Constant. (1)
It is favor using the Pythagoras theorem for detecting the hypotenuse of a triangle, only in this circumstance the hypotenuse remains constant and the other 2 legs of the triangle tin alteration, but they have to satisfy the theorem.
While Pam is moving relating apt Jim, she retains her rate of space-time campaign, averaging that her rate of period movement must come down. Since the values are squared, it does no stuff in which way the campaign is; the achieve is the same for her outbound tumble and her inbound trip.
To give some practical values: let Pam travel away from Jim by 60% of the speed of light and turn approximately after 4 annuals on her timer. If she returns by the same speed, it is obvious that she would have aged 8 annuals on her trip. However, she would find Jim to be 10 years older than while she left him, and he will have the birthday cards to show that! This ought please Pam?
Let's validate the values with equation (1) above: Jim has not moved via space, so for him: STM squared = 0 + 10 squared = 100. Since Pam has moved, we must know how distant she has moved according to Jim. She traveled at 60% of the speed of light for 10 years, so she must have moved a distance of 6 light-years,[link widoczny dla zalogowanych], accordingly for Pam: STM squared = 6 squared + 8 squared = 100, satisfying the theory.
That's it,Shock absorbing castors flat the upward from the, girls! As Pam has shown,[link widoczny dla zalogowanych], travel keeps you young
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